(2x^2-4x)/(2x^3-8x)

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Solution for (2x^2-4x)/(2x^3-8x) equation:


D( x )

2*x^3-(8*x) = 0

2*x^3-(8*x) = 0

2*x^3-(8*x) = 0

2*x^3-8*x = 0

2*x^3-8*x = 0

2*x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:-2) U (-2:0) U (0:2) U (2:+oo)

(2*x^2-(4*x))/(2*x^3-(8*x)) = 0

(2*x^2-4*x)/(2*x^3-8*x) = 0

2*x^2-4*x = 0

2*x*(x-2) = 0

x-2 = 0 // + 2

x = 2

2*x*(x-2) = 0

2*x^3-8*x = 0

2*x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

2*x*(x-2)*(x+2) = 0

(2*x*(x-2))/(2*x*(x-2)*(x+2)) = 0

( 2*x )

2*x = 0 // : 2

x = 0

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 0}

x in { 2}

x belongs to the empty set

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